Talk:Nitrile: Difference between revisions
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In this reaction, benzamine's amine is converted into a diazonium ion after an O=N+ radical adds a nitrogen and removes the hydrogens from the original nitrogen, releasing water in the process and creating a cation. Then, another benzene molecule with an activating, para, ortho directing group such as this methyl group attacks the positively charged diazonium compound and forms a bond with the positive, outermost nitrogen. A proton is lost to reform the conjugation of the attacking benzene ring. This reaction will mainly happen at the para position because of steric hindrance. [[File:Azo_Compound_Formation.png|800px]] | In this reaction, benzamine's amine is converted into a diazonium ion after an O=N+ radical adds a nitrogen and removes the hydrogens from the original nitrogen, releasing water in the process and creating a cation. Then, another benzene molecule with an activating, para, ortho directing group such as this methyl group attacks the positively charged diazonium compound and forms a bond with the positive, outermost nitrogen. A proton is lost to reform the conjugation of the attacking benzene ring. This reaction will mainly happen at the para position because of steric hindrance. [[File:Azo_Compound_Formation.png|800px]] | ||
== Synthesis of a nitrile from cyanide and halogenalkane (Tyria Heath) == | |||
[[File:Nitrile_formation_from_halogenalknane_&_CN.png|1000px]] | |||
Revision as of 22:26, 19 February 2019
Formation of a Nitrile from a Primary Amide Using Thionyl Chloride (Amelia Zoernig)
Azo Compound Formation Via Aromatic Substitution (Matt Lieberman)
In this reaction, benzamine's amine is converted into a diazonium ion after an O=N+ radical adds a nitrogen and removes the hydrogens from the original nitrogen, releasing water in the process and creating a cation. Then, another benzene molecule with an activating, para, ortho directing group such as this methyl group attacks the positively charged diazonium compound and forms a bond with the positive, outermost nitrogen. A proton is lost to reform the conjugation of the attacking benzene ring. This reaction will mainly happen at the para position because of steric hindrance.